Difference between revisions of "Talk:Contrib:KeesWouters/shell/static"

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kees
 
kees
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Hi Kees,
 
Hi Kees,
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''3. what is the best way to get max displacement DZ? Directly from Deformed shape = 0,0292?'' <br>
 
''3. what is the best way to get max displacement DZ? Directly from Deformed shape = 0,0292?'' <br>
  
Alright, about reaction forces: <br>
+
---------------
 +
BC:<br/>
 +
So the BCs given in the wiki are correct now, are not they?
 +
 
 +
Selection of layer is performed in the CALC_ELEM command:<br/>
 +
To calculate displacements (no need for selecting a layer here though):<br>
 +
resu=CALC_ELEM(reuse=resu,
 +
            MODELE=modmod,
 +
            CHAM_MATER=material,
 +
            RESULTAT=resu,
 +
            REPE_COQUE=_F(NIVE_COUCHE='SUP',),#this determines layer for the EQUIvalent stresses 'EQUI_ELNO_SIGM'
 +
            OPTION=('SIGM_ELNO_DEPL',),);      #includes data for 'DEPL' and 'SIGM_NOEU_DEPL'
 +
 
 +
I use a new field to get the results at layer ''SUP'':
 +
resuSUP=CALC_ELEM(MODELE=modmod,
 +
                CHAM_MATER=material,
 +
                RESULTAT=resu,
 +
                REPE_COQUE=_F(NIVE_COUCHE='SUP',),
 +
                OPTION=('SIGM_ELNO_DEPL','EQUI_ELNO_SIGM',),);
 +
 
 +
you can also add e.g:
 +
resuINF=CALC_ELEM(MODELE=modmod,
 +
                CHAM_MATER=material,
 +
                RESULTAT=resu,
 +
                REPE_COQUE=_F(NIVE_COUCHE='INF',),
 +
                OPTION=('SIGM_ELNO_DEPL','EQUI_ELNO_SIGM',),);
 +
 
 +
and add them in the IMPR_RESU command. Do the same for 'MOY' for central layer if needed.
 +
 
 +
 
 +
About reaction forces: <br>
 
* 1: I added the '''table''' command: you get the total reaction forces. But I know I used a parameter that gives the requested field at all nodes. Need to search a bit.
 
* 1: I added the '''table''' command: you get the total reaction forces. But I know I used a parameter that gives the requested field at all nodes. Need to search a bit.
 
* 2: correct: look at the end of the contribution. But The strange thing is that the midside node have large positive reactions whereas the corner nodes have negative reactions. Might be correct though (????), but need to look at it. The diameter of the nodes indicate value of reaction forces.  
 
* 2: correct: look at the end of the contribution. But The strange thing is that the midside node have large positive reactions whereas the corner nodes have negative reactions. Might be correct though (????), but need to look at it. The diameter of the nodes indicate value of reaction forces.  
 
* I normally look at the shape and see what is the maximum value. In Salome 4.x the maximum and minimum values were displayed in the scale, but now these values seems to be rounded. The is an option to extract the min/max displacements/stress/strain values. But I never used it, so need the search for it.
 
* I normally look at the shape and see what is the maximum value. In Salome 4.x the maximum and minimum values were displayed in the scale, but now these values seems to be rounded. The is an option to extract the min/max displacements/stress/strain values. But I never used it, so need the search for it.
 +
 +
-------------------

Revision as of 12:50, 10 March 2010

Hoi Bridge

Very nice start. I added the coordinates of the point P1 .. P16. Did you give all coordinate by hand?

Regarding the local stresses SIXX, SIYY etc: did you take the SUP layer?

kees


Hi Kees, our's tutorial grows very rapidly :D
i used your's files from forum,
for SIXX,SIYY,SIXY i used: resuSUP_SIGM_NOEU_DEPL__________ -> scalar map
where can I choose the SUP layer?


- there was error in bc, correct are: Lleft: (DX=0.0,DY=0.0,DZ=0.0); Lright: (DZ=0.0); Ltop,Lbot: free
- i fixed it in:

  • Create two groups for boundary conditions
  • Reactions

- You are right, area 73.3 is correct

  • my ideas:

1. export list of ReactionForces at nodes of Nleft and Nright group to txt file,
2. export ReactionForces at nodes of Nleft and Nright group to to med file and make scalar maps or vector
3. what is the best way to get max displacement DZ? Directly from Deformed shape = 0,0292?


BC:
So the BCs given in the wiki are correct now, are not they?

Selection of layer is performed in the CALC_ELEM command:
To calculate displacements (no need for selecting a layer here though):

resu=CALC_ELEM(reuse=resu,
            MODELE=modmod,
            CHAM_MATER=material,
            RESULTAT=resu,
            REPE_COQUE=_F(NIVE_COUCHE='SUP',),#this determines layer for the EQUIvalent stresses 'EQUI_ELNO_SIGM'
            OPTION=('SIGM_ELNO_DEPL',),);      #includes data for 'DEPL' and 'SIGM_NOEU_DEPL'

I use a new field to get the results at layer SUP:

resuSUP=CALC_ELEM(MODELE=modmod,
                CHAM_MATER=material,
                RESULTAT=resu,
                REPE_COQUE=_F(NIVE_COUCHE='SUP',),
                OPTION=('SIGM_ELNO_DEPL','EQUI_ELNO_SIGM',),);

you can also add e.g:

resuINF=CALC_ELEM(MODELE=modmod,
                CHAM_MATER=material,
                RESULTAT=resu,
                REPE_COQUE=_F(NIVE_COUCHE='INF',),
                OPTION=('SIGM_ELNO_DEPL','EQUI_ELNO_SIGM',),);

and add them in the IMPR_RESU command. Do the same for 'MOY' for central layer if needed.


About reaction forces:

  • 1: I added the table command: you get the total reaction forces. But I know I used a parameter that gives the requested field at all nodes. Need to search a bit.
  • 2: correct: look at the end of the contribution. But The strange thing is that the midside node have large positive reactions whereas the corner nodes have negative reactions. Might be correct though (????), but need to look at it. The diameter of the nodes indicate value of reaction forces.
  • I normally look at the shape and see what is the maximum value. In Salome 4.x the maximum and minimum values were displayed in the scale, but now these values seems to be rounded. The is an option to extract the min/max displacements/stress/strain values. But I never used it, so need the search for it.